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12 February, 07:52

Find the third iterate, x3, of the function f (x) = 3x + 5 for an initial value of x0 = 1.

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  1. 12 February, 11:45
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    Find the third iterate, x3, of the function f (x) = 3x + 5 for an initial value of x0 = 1. x1 = 3 (1) + 5 = 8 ... x2 = 3 (8) + 5 = 29 ... x3 = 3 (29) + 5 = 92
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