3x^2 - 16x + 2 = 0

Part A: Describe the solution (s) to the equation by just determining the radicand.

Question

Mathematics

Billy Chase

13 June, 02:47

3x^2 - 16x + 2 = 0

Part A: Describe the solution (s) to the equation by just determining the radicand.

+2

Answers (1)

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Yamilet Gross · Answer 1

A = 3 b = - 16 and c = 2

the radicand would be

sq root (b^2 - 4*a*c) =

sq root (256 - 4*3*2) =

sq root (232)

So the roots will be real and not complex.

3x^2 - 16x + 2 = 0Part A: Describe the solution (s) to the equation by just determining the radicand.

3x^2 - 16x + 2 = 0

Part A: Describe the solution (s) to the equation by just determining the radicand.