Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

177,147

88,572

88,575

177,144

First, we need to solve for the common ratio from the data given by using the equation.

a (n) = a (1) r^ (n-1)

59049 = 3 r^ (10-1)

19683 = r^9

r = 3

Then, we can find the sum by the expression:

S (n) = a (1) (r^n - 1) / 1-r

S (10) = 3 (3^10 - 1) / 3-1

S (10) = 88572