A cylinder rod formed from silicon is 46.0 cm long and has a mass of 3.00 kg. The density of silicon is 2.33 g/cm^3. What is the diameter of the cylinder? (the volume of cylinder is given by (pi) r^2h, where r is the radius and h is the length)

I make it 6 cm diameter (well ... 5.97 cm really, but it depends how many places you take π to!).

Explanation:

You have been given density (d) and mass (m), so first you can determine volume (v).

d = m/v therefore v = m/d = 3000/2.33 = 1287.55 c m^3

Now you have the volume and the length (L) from which you can work out the cross sectional area, π. r2, and from that the diameter.

Volume v = π. r2. L therefore r = √ v / π. L and diameter D = 2r = √ (v π. L) x 2.

So plugging in the numbers gives: D = √ (1287.55 / 3.142X46) X2 = 5.97 cm.

Hello there.

A cylinder rod formed from silicon is 46.0 cm long and has a mass of 3.00 kg. The density of silicon is 2.33 g/cm^3. What is the diameter of the cylinder? (the volume of cylinder is given by (pi) r^2h, where r is the radius and h is the length)

5.97 cm.