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31 July, 10:53

For each initial approximation, determine graphically what happens if Newton's method is used for the function whose graph is shown:

x1=0, x1=4, x1=1, x1=5, x1=3

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  1. 31 July, 11:16
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    The next guess for x, which will be x_2, will be the x-intercept of the line whose slope is the slope of the function at x_1.

    a) The slope is positive on a portion of the graph that has a horizontal asymptote. Newton's method will give guesses that approach negative infinity.

    b) The slope is zero. Newton's method will give a guess of infinity or "overflow" or "not a number" or "error" depending on how division by zero is treated. The tangent line is parallel to the x-axis, so there is no x-intercept.

    c) It looks like the slope is negative, but will give a guess in the same region as for answer (a). (For guesses near 2, it is likely Newton's method would converge on the solution near x=2. The function is well-behaved in a small area there, so x_1 must be "close enough" for there to be convergence.)

    d) The slope appears to be zero at x=4, so the answer is the same as for (b).

    e) The iteration method will give guesses that are likely to converge to the solution near x=6.
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