There are 20 children in the cast of a class play, and 8 of the children are boys. Of the boys, 4 have a speaking part in the play, and of the girls, 8 do not have a speaking part in the play. If a child from the cast of the play is chosen at random, what is the probability that the child has a speaking part?

Question

Mathematics

Korbin Hunt

6 May, 00:28

There are 20 children in the cast of a class play, and 8 of the children are boys. Of the boys, 4 have a speaking part in the play, and of the girls, 8 do not have a speaking part in the play. If a child from the cast of the play is chosen at random, what is the probability that the child has a speaking part?

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Answers (1)

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Mikaela Byrd · Answer 1

Probablity is (desired outcomes) divided by (total possible outcomes) or (d) / (t)

20 total

8 boys

girls=20-8-12

4 boys have speaking parts

8 out of 12 girls do not have speaking part so 12-8=4 girls do have a speaking part

4 boys and 4 girls have speaking parts

4+4=8

8 speaking parts total 20 total people so

desired outcomes=8

total possible=20

8/20=4/10=2/5

probability is 2/5