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31 August, 14:51

What are three consecutive positive integers with a sum of 120

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Answers (2)
  1. 31 August, 15:15
    0
    Consetuve integers are 1 apart

    they are n, n+1, n+2

    so

    n+n+1+n+2=120

    3n+3=120

    miknus 3 both sides

    3n=117

    divide both sides by 3

    n=39

    n+1=40

    n+2=41

    the numbers are 39,40,41
  2. 31 August, 18:00
    0
    Consecutive numbers are numbers right next to each other like 1 2 3 so I think you'd divide 120 by 3. But I think the numbers are 39 40 and 41
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