Solve the given system of linear equations for y: 4x + y = - 11 and x + 2y = - 8

4x+y=-11

y=-11 - (4x)

x+2y=-8

2y=-8-x

y = (-8-x) / 2

y=-11-4 (-8-2y)

y=-11 - (32-8y)

y=-11+32+8y

y=21+8y

0=21+8y-y

0=21+7y

-21=7y

y=-3

4x + y = - 11

4x - 4x + y = - 11 - 4x

y = - 11 - 4x

4x - 11 - 4x = - 11

4x - 4x - 11 = - 11

0x - 11 = - 11

+11 + 11

0x = 0

0 0

x = 0

4 (0) + y = - 11

0 + y = - 11

+0 + 0

y = - 11

(x, y) = (0, - 11)

x + 2y = - 8

x - x + 2y = - 8 - x

2y = - 8 - x

2 2

y = - 4 - 1/2x

x + 2 (-4 - 1/2x) = - 8

x - 8 - x = - 8

x - x - 8 = - 8

0x - 8 = - 8

+8 + 8

0x = 0

0 0

x = 0

0 + 2y = - 8

+0 + 0

2y = - 8

2 2

y = - 4

(x, y) = (0, - 4)