F (1) = 16 f (n) = (n-1) + 2n what is f (4)

Question

Mathematics

Bosco

1 September, 22:04

F (1) = 16 f (n) = (n-1) + 2n what is f (4)

+3

Answers (2)

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Damian Pena · Answer 1

F (1) = 16

f (n) = (n - 1) + 2n

f (4) = 64

f (4) = (4 - 1) + 2 (4)

f (4) = 3 + 8

f (4) = 11

Yareli Osborn · Answer 2

F (4) = (4-1) + 2*4=11 ...

This seems a bit too easy though, did you mean f (n) = f (n-1) + 2n? In this case:

f (1) = 16

f (2) = 16+2*2=20

f (3) = 20+2*3=26

f (4) = 26+2*4=34