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12 October, 06:28

A=xy if 2x+y=16 find the maximum

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  1. 12 October, 08:39
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    Solve the second for y ...

    y=16-2x, then the A=xy becomes:

    A=x (16-2x)

    A=16x-2x^2

    dA/dx=16-4x, d2A/dx2=-4

    Since acceleration, d2A/dx2, is a constant negative, when velocity, dA/dx=0, A (x) is at an absolute maximum value ...

    dA/dx=0 when 4x=16, x=4 and that maximum value is:

    A (4) = 16x-2x^2=32 u^2
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