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25 July, 07:45

A water tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an average rate of 650 gallons per day

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  1. 25 July, 11:00
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    In the question, it is already mentioned that the water tank holds = 24,000 gallons

    In the given question it is also mentioned that the need is to find the time required to use 2/3 of the total water that the tank holds.

    So the need is to find the amount of water that equals 2/3 of the total water in the tank.

    Then

    Quantity of water that needed to be used = [24000 * (2/3) ] gallons

    = 16000 gallons

    In the problem it is also mentioned that the average rate of consumption per day is 650 gallons.

    So

    650 gallons of water used in = 24 hours

    16000 gallons of water will be used in = [ (24/650) * 16000] hours

    = 590.77 hours

    So the time required to consume 2/3 of the total water in the tank is 590.77 hours.
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