What's the perimeter of 80 and115l

P=2 (l+w)

P = 2 (80 + 1151)

P = 2 (1231)

P = 2462

The given known values are: Length of 4 cm Width is unknown Perimeter is 34 cm Find the dimensions of the rectangle. Since the geometric formula for perimeter is:

P = 2 (l + w)

L = 2w - 4 cm

W = ?

Derivation and solution:

34 = 2 (2w - 4) + 2w

34 = 4w - 8 + 2w

42 = 6w 42/6 = w

W = 7 cm

34 = 2l + 2 (7)

34 = 2l + 14

2l = 34 - 14

2l = 20

L = 20/2

L = 10 cm