There are a total of 20 lions, tigers and bears. If the number of tigers is 2 more than the number of lions and the number of bears is 1 more than the number of tigers, find the number of each.

Number of tiguers: x + 2

Number of Lions: x

Number of bears: (x+2) + 1 = (x+3)

We can suggest this equation:

(x+2) + (x) + (x+3) = 20

3x+5=20

3x=20-5

3x=15

x=15/3

x=5.

Therefore:

Number of tiguers: x + 2=5+2=7

Number of Lions: x=5

Number of bears: (x+2) + 1 = (x+3) = 5+3=8.

Answer: there are 7 tiguers, 5 lions and 8 bears.