Find two consecutive integers such that the sum of the first and twice the second is 74

Let the consecutive integers be x and x+1

x+2 (x+1) = 74

or x+2x+2=74

3x=74-2=72

x=72/3=24

x+1=24+1=25

hence numbers are 24 and 25

Consecutive integers are 1 apart

they are x and x+1

sum of firt and twice the 2nd is 74

sum is addition

twice is 2 times

x+2 (x+1) = 74

distribute

x+2x+2=74

add like terms

3x+2=74

minus 2 both sides

3x=72

divide both sides by 3

x=24

x+1=25

the numbers are 24 and 25