What is the P (getting a 3 on the second die given that you got a 2 on the first die) ?

I'm not sure if it is 1/6 or 1/36 because of the formula for independent A and B events

I think it is 1/6 because the possibilities are present when the first die has already got a 2. "Got a 2 on the first die" already happened.

If the statement is "getting a 3 on the second die and a 2 on the first die" then the answer should be 1/36.