How many solutions does the system of two equations shown have?

y=3 (x+4)

y=3 (x-4)

There is no solution. if you are using the two equations to solve for y and x.

you can plug one equations into the other.

substituting one of the y gives ...

3 (x+4) = 3 (x-4)

: both sides by 3 gives x+4=x-4

get x on one side and numbers on the other

x-x = 4+4

and x-x will give you a 0 for the left side

therefore 0 = 4+4 ... not true.