What is x2+7x+12=0 in standard form

X² + 7x + 12 = 0

x = - (7) + / - √ ((7) ² - 4 (1) (12))

2 (1)

x = - 7 + / - √ (49 - 48)

2

x = - 7 + / - √ (1)

2

x = - 7 + / - 1

2

x = - 7 + 1 x = - 7 - 1

2 2

x = - 6 x = - 8

2 2

x = - 3 x = - 4

Not sure what standard form is, but I can solve for x

so I'm assuming that x2 means x squared or x^2 so

x^2+7x+12=0

since it equals zero, if we can factor it, then

if we have xy=0 then x and/or y=0 so

to factor x^2+7x+12

find what 2 numbers multiply to get 12 and add to get 7 so

12=2 times 2 times 3 or 2 times 6 or 1 times 12 or 3 times 4

the numbesr are 4 times 3 so

x^2+7x+12

facotrs out to

(x+4) (x+3) so

x^2+7x+12=0

(x+4) (x+3) = 0

set each to zero

x+4=0 and x+3=0

x+4=0

subtract 4 form both sides

x=-4

x+3=0

subtract 3 from both sides

x=-3

x=-4 or - 3