Ask Question
22 January, 17:34

How do I find the horizontal and vertical asymptotes of f (x) = 2/x^2-2x-3?

Also would like to check if my x and y intercepts are correct.

+4
Answers (1)
  1. 22 January, 19:27
    0
    I love doing this

    for a function p (x) / q (x)

    if degree of p (x)
    if degrees are equal, divide linear coefients

    horzontal assemtotes

    first simplify

    then set denom to zero and solve for x values

    so

    f (x) = 2 / (x^2-2x-3)

    less so HA=y=0

    doesn't cross HA

    VA, set denom to zer

    x^2-2x-3=0

    (x-2) (x-1) = 0

    HA, at x=1 and x=2

    xint, set y=0 and solve

    not applicatble, no xint

    yint, set x=0

    ying=-2/3

    HA is y=2, doesn't cross it

    VA's at x=1 and x=2

    no xint

    yint at (0,-2/3)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How do I find the horizontal and vertical asymptotes of f (x) = 2/x^2-2x-3? Also would like to check if my x and y intercepts are correct. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers