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2 November, 22:29

X+3y=3

2x-4y=6

solve the equations

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Answers (2)
  1. 2 November, 23:38
    0
    So divide the second equation by 2

    x-2y=3

    the first equation is

    x+3y=3

    subsitute

    3=3 so therefor

    x-2y=x+3y

    subtract x from both sides

    -2y=3y

    add 2y to both sides

    0=5y

    ofviously y=0 so subsitute

    x-2y=3

    x - (2) 0=3

    x-0=3

    x=3

    x=3

    y=0
  2. 3 November, 01:29
    0
    Subtract the second equation from double the first equation:

    2x+6y-2x - (-4y) = 0

    10y=0

    Therefore, y=0. Substituting this into the first equation, we see that:

    x+3 (0) = 3

    x=3

    Therefore, x=3. The solution to this system is x=3, y=0, or (3, 0).
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