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8 February, 10:46

Find dy/dx when y=0 if xcosy-sinx-2=0

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  1. 8 February, 11:30
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    xcos (y) - - > For this part, use the product rule, which would mean

    cosy - xsiny * dy/dx

    sinx's derivative is just cosx, so we get as a final answer

    cosy - xsiny * dy/dx - cosx = 0

    -xsiny * dy/dx = cosx - cosy

    dy/dx = cosx - cosy / - xsiny

    When y=0,

    dy/dx = cosx - cosy / - xsiny

    dy/dx = cosx - cos (0) / - xsin (0) [note: sin (0) = 0]

    dy/dx = undefined [since you can't divide by 0]
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