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15 December, 16:26

Determine the type and number of solutions of x^2-8x+16=0

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Answers (2)
  1. 15 December, 18:47
    0
    This would factor to (x-4) (x-4) = 0

    The discriminant would be b^2-4ac___64-4*1*16=0

    The factors show x=4, x=4; a double root and the discriminant shows 0 which is also 1 real rational zero
  2. 15 December, 19:58
    0
    Type?

    anyway, what 2 numbers multiply to get 16 and add to get - 8

    -4 and - 4

    (x-4) (x-4) = 0

    (x-4) ²=0

    set to zeo

    x-4=0

    x=4

    there is 1 soltuion repeated twice (x=4)
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