The length of Marshall's poster is 2 times its which if the perimeter is 72 inches what is the area of the poster

From the information given, the dimensions seem to allude to a rectangular shaped poster. Let us assume this is so.

Let the width of the poster be x

Let the length of the poster be 2x

2w + 2L = P

where P = Perimeter, w = width, L = length.

2 (x) + 2 (2x) = 72

2x + 4x = 72

6x = 72

x = 72 / 6

x = 12

Width is 12 inches

Length is 2 * 12 = 24 inches

Area = L X W

Area = 24 * 12

Area = 288 inch²