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7 August, 10:18

How do you simplify 8y to the power of two + 7y+4-3 (2y to the power of two-5y-8)

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  1. 7 August, 11:18
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    8y²+7y+4-3 (2y²-5y-8)

    =64y+7y+4-3 (4y-5y-8)

    =71y+1 (4y-5y-8)

    =71y+1 (-y-8)

    =71y+-y-8

    =71y-y-8

    =70y-8

    Try this, see if it works.
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