Ask Question
1 May, 06:37

How many real solution does the equation x^7+14x^5+16x^3+30x-560=0

+3
Answers (1)
  1. 1 May, 07:55
    0
    Consider the given equation to be f (x) whose first derivative is positive for all real x. This implies f (x) is a strictly increasing function. Thus it has only 1 root.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many real solution does the equation x^7+14x^5+16x^3+30x-560=0 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers