Find the area of a sector with a central angel of 300 degrees and a radius of 14.6 mm. Round to the nearest tenth.

Thats pretty hard, but I get it ... it's highschool

Area of a cirlce=πr²

a circle has 360º

Therefore:

πr²/360º=area of a sector/degrees of this sector

area of a sector = (πr²) (degrees of this sector / 360º

dа ta:

r=14.6 mm

degrees of this sector=300º

area of a sector=π (14.6 mm) ² (300º) / 360º=177.6333 ... π mm²≈117.63π mm².

if π≈3.1416 then:

Area of a sector=177.63 (3.1416) mm²=558.05 mm²

Answer: the area of this sector is 177.63π mm² or 558.05 mm².