Ask Question
9 July, 20:40

Use substitution to solve s+a=4 and 35+5a=2550

+4
Answers (2)
  1. 9 July, 21:59
    0
    S + a = 4

    35 + 5a = 2550

    From the second equation:

    35 + 5a = 2550

    5a = 2550 - 35

    5a = 2515

    a = 2515/5

    a = 503

    From s + a = 4

    s + 503 = 4

    s = 4 - 503

    s = - 499

    Therefore a = 503, s = - 499
  2. 9 July, 23:31
    0
    35+5 (4-s) = 2550

    35+20-5s=2550

    55-5s=2550

    -55 - 55

    -5s = 2495

    s = - 499

    -499 + a = 4

    +499 + 499

    a = 503
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Use substitution to solve s+a=4 and 35+5a=2550 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers