Use substitution to solve s+a=4 and 35+5a=2550

Question

Mathematics

Simeon Lee

9 July, 20:40

Use substitution to solve s+a=4 and 35+5a=2550

+4

Answers (2)

Know the Answer?

Hailie Calhoun · Answer 1

S + a = 4

35 + 5a = 2550

From the second equation:

35 + 5a = 2550

5a = 2550 - 35

5a = 2515

a = 2515/5

a = 503

From s + a = 4

s + 503 = 4

s = 4 - 503

s = - 499

Therefore a = 503, s = - 499

Jaidyn Dunlap · Answer 2

35+5 (4-s) = 2550

35+20-5s=2550

55-5s=2550

-55 - 55

-5s = 2495

s = - 499

-499 + a = 4

+499 + 499

a = 503