The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t2. How long after launch does the projectile return to the ground?

a) 2 seconds

b) 4 seconds

c) 14 seconds

d) 16 seconds

Question

Mathematics

Raisin

30 May, 17:30

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t2. How long after launch does the projectile return to the ground?

a) 2 seconds

b) 4 seconds

c) 14 seconds

d) 16 seconds

+4

Answers (2)

Know the Answer?

Jada Campos · Answer 1

When it returns to the ground, h = 0

32t - 16t^2 = 0

t (32 - 16t) = 0

t = 0 or 32 = 16t

t = 0 or t = 2

Therefore, the projectile returns to the ground after 2 seconds.

Alani Woodward · Answer 2

We are given with the projectile function expressed as h = 32t - 16t2. To get the time of flight, we differentiate the function and then equate to zero. This is equal to dh/dt = 32 - 32t = 0; t is equal to 1 second. The total time is twice the first-half time equal to 2 seconds.

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t2. How long after launch does the projectile return to the ground?a) 2 secondsb) 4 secondsc) 14 secondsd) 16 seconds

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t - 16t2. How long after launch does the projectile return to the ground?

a) 2 seconds

b) 4 seconds

c) 14 seconds

d) 16 seconds