Name the focus of y = 0.6x^2.

Parabola

remember that

parabola equation is

4p (y-k) = (x-h) ^2 for a verticl parabola

p=distance from vertex to focus and from vertex to directix

solve for p, k, h

y=0.6x^2

4p (y-0) = (x-0) ^2

divide both sides by 4p

(y-0) = 1/4p times (x-0) ^2

y=0.6x^2

1 / (4p) = 0.6

find p

multiply 4p

1=2.4p

divide 2.4

1/2.4=p

h=0, k=0

vertex=0,0

opens up so go up to find focus

(0,0)

0+1/2.4=1/2.4

focus is at (0,1/2.4)