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28 October, 04:53

Which recursive formula can be used generate the sequence shown where f (1) = 5 and n>1?

5,-1,-7,-13,-19, ...

A) f (n+1) = (n) + 6

B) f (n) = f (n+1) - 6

C) f (n+1) = f (n) - 6

D) f (n+1) = - 6f (n)

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Answers (1)
  1. 28 October, 07:25
    0
    So we notice that the difference between the nubmers is 6 (5-6=-1, - 1-6=-7, etc)

    so therefor it must be something with - 6, and n>1 so

    f (n) = - 6n

    the difference to the next erm is 6 so the answe ris C

    f (n+1) = f (n) - 6

    C
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