The perimeter of a rectangle is 154 meters. If the width is 40% of the length, find the dimensions of the rectangle

The answer is 14x11 for the rectangle

The equation for for perimeter of a rectangle is

2w + 2L = 154 meters

and we know that

w =.4L

so all we have to do is plug in what we know

2 (.4L) + 2L = 154

.8L + 2L = 154

2.8L = 154

L = 55

now we know L we can solve for w with our first equation

2w + 2 (55) = 154

2w = 44

w = 22

so the length is 55 and our width is 22.

Let check

55 *.4 = 22 so we are correct.