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5 June, 12:39

George found that he blinked 85 times in 15 minutes at this rate how many minutes pass during 51 blinks math

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  1. 5 June, 14:07
    0
    So 85 is to 15 mins

    85:15

    85/15=17/3

    17:3=51:x

    17/3=51/x

    multiply both sides by 3x to clear fraction

    17x=153

    divide both sides by 17

    x=9

    9 mins passed
  2. 5 June, 15:36
    0
    Since they blink at the same rate, the number of blinks per minute must be equal between the two periods of time. Therefore,

    85 blinks / 15 minutes = x blinks per minute

    51 blinks / y minutes = x blinks per minute

    Since the rates are equal, you can set these two proportions equal to each other.

    85 blinks / 15 minutes = 51 blinks / y minutes

    85 * y = 51 * 15

    y = (51 * 15) / 85 = 9 minutes
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