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14 May, 20:54

The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?

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  1. 14 May, 22:08
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    The perimeter (P) of a polygon is all the values of all the sides added together. (Length+Length+Width+Width) If the length (L) of the rectangle is 2 feet longer than twice the width (W), then L=2W+2. So now the perimeter is 2W+2+2W+2+W+W = P. This simplifies to 6W+4=P. If we know the perimeter is 244, then 6W+4=244. Then subtract four and divide by 6. W=40. If L=2W+2, then L=2 (40) + 2, or L=82. SO ...

    The width is 40 feet

    The length is 82 feet
  2. 14 May, 23:38
    0
    Peri = 2A+2B

    244 = 2 (2+2x) + 2 (x)
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