The sum of 2 numbers is 50. The first number is 43 less than twice the second number. Write and solve a system of equations to find the 2 numbers

I will use the Substitution Method:

Method 1 (Substitution):

x = first number

y = second number

x + y = 50 Equation 1

x = 2y - 43 Equation 2

Substituting Equation 2 into Equation 1:

2y - 43 + y = 50

2y + y = 93 Add 43 to each side.

3y = 93 Addition.

y = 31 Divide each side by 3.

Substituting value of y into Equation 1:

x + 31 = 50

x = 19 Subtract 31 from each side.

Answer: x = 19 and y = 31

The first nunber is 43 abd tve second is 7