A speedy river barge bound for New Orleans, Louisiana leaves Baton Rouge at 9:00 a. m. and travels at a speed of 10 miles per hour. A rail transport freight also bound for New Orleans leaves Baton Rouge at 1:30 p. m. on the same day. The train travels at 25 miles per hour, both the barge and train will travel 100 miles to reach New Orleans. How far will the train travel before catching up to the barge?

Question

Yesenia Castillo

28 August, 04:51

+3

Answers (1)

Know the Answer?

Jaydan Salazar · Answer 1

Okay i get it now

1) At 1.30 p. m. the barge has already traveled 4.5 X 10 = 45 miles.

To catch up it will take the train 25-10 = 15miles