Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.

A) x = One fourth, solution is not extraneous

B) x = One fourth, solution is extraneous

C) x = 3, solution is not extraneous

D) x = 3, solution is extraneous

An extraneous solution is a root that when substituted to the original equation, the answer becomes invalid. In this respect, the equation is square root (8x + 1) = 5; 8x + 1 = 25; x1 = 3; 8x + 1 = - 25; x2 = - 26/8 = - 13 / 4. Upon substitution, square root of (8*3 + 1) = 5, this is valid. Hence the answer to this question is C.