2. Solve the system using substitution.

2x+2y=38

y=x+3

A. (8,11)

B. (4,7)

C. (35/4, 47/4)

D. (-4,-7)

2x+2y=38

y=x+3

First you would substitute the y for x+3

2x+2 (x+3) = 38

You would multiply the 2 by the x+3

2x+2x+6=38

Add the 2x and the 2x

4x+6=38

Subtract the 6 on both sides

4x=32

Divide the 4 on both sides

x=8

Now substitute the x in the second problum for 8

y=8+3

Add the 8 and the 3 to solve for y

y=11

Your answers

x=8

y=11

the correct answer would be A: (8,11)