2 dice are rolled. What is the probability that the sum of the numbers rolled is a number greater than or eaqual to 5

2 + 3 = 5 > = 5;

2 + 4 = 6 > = 5;

2 + 5 = 7 > = 5;

2 + 6 = 8 > = 5;

3+2 = 5 > = 5;

3 + 3 = 6 > = 5;

3 + 4 = 7 > = 5;

3 + 5 = 8 > = 5;

3 + 6 = 9 > = 5;

4+1 = 5 > = 5;

4+2 = 6 > = 5;

4+3 = 7 > = 5;

4+4 = 8 > = 5;

4+5 = 9 > = 5;

4+6 = 10 > = 5;

5+1 = 6 > = 5;

5+2 = 7 > = 5;

...

6 + 6 = 12 > = 5;

Number of ways it can happen = 27;

Total number of outcomes = 6*6 = 36;

Probability of an event happening = Number of ways it can happen / Total number of outcomes = > Probability = 27/36 = 0.75;