The perimeter of ABC is 30 feet. AB=5x-7, BC=3x+1, AC=4x. List the angles of ABC in order from smallest to largest

A) Angle A, B, C

B) Angle A, C, B

C) Angle C, B, A

D) Angle C, A, B

Lets say we have a triangle ABC

if A is the biggest angle, the side oposite that angle (BC) will be the longest

so

perimiter=AB+BC+AC

P=30=5x-7+3x+1+4x

find x

30=5x-7+3x+1+4x

30=5x+3x+4x-7+1

30=12x-6

add 6

36=12x

divide 12

3=x

evaluate each

AB=5 (3) - 7=15-7=22

BC=3 (3) + 1=9+1=10

AC=4 (3) = 12

AB>AC>BC

the oposite one

C>B>A

smallest to largest

A
answer is option A