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21 May, 21:37

Find the x intercept of the parabola with vertex (2 13) and y intercept (0 5)

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  1. 21 May, 22:40
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    Y = a (x - 2) ^2 + 13 ... vertex form y = a (x - h) ^2 + k ... with vertex (h, k)

    5 = a (0 - 2) ^2 + 13

    5 = 4a + 13

    - 8 = 4a

    -2 = a

    y = - 2 (x - 2) ^2 + 13 ... now let y=0 and find the x intercept

    0 = - 2 (x - 2) ^2 + 13 ... subtract 13

    -13 = - 2 (x - 2) ^2 ... divide by - 2

    -13/-2 = (x - 2) ^2 ... simplify

    13/2 = (x - 2) ^2 ... take the sq rts.

    √ (13/2) = x - 2 ... √6.5 = 2.55 ... add 2

    x = 4.55
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