Y = - x + 4

x + 2y = - 8

How many solutions does this linear system have

one solution: (8, 0)

one solution: (0, 8)

no solution

infinite number of solutions

Question

Mathematics

Desirae Key

30 December, 15:26

Y = - x + 4

x + 2y = - 8

How many solutions does this linear system have

one solution: (8, 0)

one solution: (0, 8)

no solution

infinite number of solutions

+4

Answers (1)

Know the Answer?

Atticus · Answer 1

Y = - x + 4 ... so sub in - x + 4 in for y in the other equation

x + 2y = - 8

x + 2 (-x + 4) = - 8

x - 2x + 8 = - 8

x - 2x = - 8 - 8

-x = - 16

x = 16

y = - x + 4

y = - 16 + 4

y = - 12

one solution (16,-12)

Y = - x + 4x + 2y = - 8How many solutions does this linear system haveone solution: (8, 0)one solution: (0, 8)no solutioninfinite number of solutions

Y = - x + 4

x + 2y = - 8

How many solutions does this linear system have

one solution: (8, 0)

one solution: (0, 8)

no solution

infinite number of solutions