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14 January, 11:07

Cot (pi/2-x) / Cosx

**I know that the answer to the problem is tanxsecx, but how do you get to that answer?

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  1. 14 January, 14:38
    0
    hello:

    Cot (pi/2-x) = tanx

    Cot (pi/2-x) / Cosx = tanx/cosx = tanx * (1/cosx) = tanx * secx

    because 1/cosx = secx
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