A ball is thrown from an initial height of

4 feet with an initial upward velocity of

29 ft/s. The ball's height h

(in feet) after t

seconds is given by the following.

Question

Mathematics

Chaz Heath

6 August, 13:28

A ball is thrown from an initial height of

4 feet with an initial upward velocity of

29 ft/s. The ball's height h

(in feet) after t

seconds is given by the following.

+3

Answers (1)

Know the Answer?

Krista Stuart · Answer 1

We are using simple gravity as a constant (ignoring air resistance and change in height)

a=-g integrating with respect to t

v=-gt+C where C is the initial velocity ...

v=-gt+29 integrating again with respect to time ...

h = (-gt^2) / 2+29t+C where C is the initial height of the ball ...

h (t) = - 16t^2+29t+4

A ball is thrown from an initial height of4 feet with an initial upward velocity of29 ft/s. The ball's height h(in feet) after tseconds is given by the following.

A ball is thrown from an initial height of

4 feet with an initial upward velocity of

29 ft/s. The ball's height h

(in feet) after t

seconds is given by the following.