Ten percent of the reds are added to twenty percent of the blues, and the total is 24. Yet the product of the number of reds and 3 exceeds the number of Blues by 20. How many are red and how many are blue?

0.10r + 0.20b = 24

3r = b + 20 ... b = 3r - 20

0.10r + 0.20 (3r - 20) = 24

0.10r + 0.60r - 4 = 24

0.70r = 24 + 4

0.70r = 28

r = 28/0.70

r = 40 < = = = there are 40 reds

0.10r + 0.20b = 24

0.10 (40) + 0.20b = 24

4 + 0.20b = 24

0.20b = 24 - 4

0.20b = 20

b = 20/0.20

b = 100 < = = = there are 100 blues