Julian and stacey needed 10 liters of water to fill a tank. Stacey filled the tank with 3 11/12 liters of water. Julian poured 1 2/5 liters less than

Stacey into the tank. How much more water is still needed to fill the tank?

In this problem it is given that the amount of water needed by Julian and Stacey to fill the tank is 10 liters. Also Stacey filled the tank with 3 11/12 liters and Julian filled the tank with 1 2/5 liters. So let us first calculate the total waters pored by Stacey and Julian.

Amount of water pored by Julian and Stacey = 3 11/12 + 1 2/5

= (47/12) + (7/5)

= (235 + 84) / 60

= 319/60

= 5.32

So the amount of water jointly poured by Julian and Stacey is 5.32 liters.

Amount of water still needed to fill the tank = (10 - 5.32) liters

= 4.68 liters.

So 4.68 liters of water is required to fill the tank completely.