The length of a rectangle is 5 feet more than twice the width. The perimeter is 130 feet. Find the dimensions.

So,

The problem tells us that the length of the rectangle is 5 feet more than twice the width.

Mathematically:

length = 5 + 2width

l = 5 + 2w

We know that the perimeter is 2l + 2w.

2l + 2w = 130

2 (5 + 2w) + 2w = 130

Distribute

10 + 4w + 2w = 130

Collect Like Terms

10 + 6w = 130

Subtract 10 from both sides

6w = 120

Divide both sides by 6

w = 20

The width is 20.

Since

l = 5 + 2w

Substitute

l = 5 + 2 (20)

Multiply

l = 5 + 40

Collect Like Terms

l = 45

The length is 45.

Check

2l + 2w = 130

2 (45) + 2 (20) = 130

90 + 40 = 130

130 = 130

Width: 20 ft.

Length: 45 ft.