A small business employs 6 women and 4 men. The manager randomly selects 3 of them to be on a team. What is the probability that all 3 are women?

6 women + 4 men = 10

6 womens / 10 people = 60 percent

6/10 = 3/5

I believe the chances are 1:3, in ratio form, because the ration of women to men is 2:3.

Because the fact that there are 2:3 women, you'd take the opposing ratio in contrast to how likely it would be.

I think.