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15 December, 10:58

Solve 2x^2 + 3x - 7 = x^2 + 5x + 39 for x.

A. x = - 6 + square root 82

B. x = - 6+2 square root 17

C. x = 1 + square root 33

D. x = 1 + square root 47

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Answers (1)
  1. 15 December, 11:43
    0
    2x^2 + 3x - 7 = x^2 + 5x + 39 =

    2x^2 - x^2 + 3x - 5x - 7 - 39 = 0

    x^2 - 2x - 46 = 0

    x = (-b (+-) sqrt b^2 - 4ac) / 2a

    x = ( - (-2) (+-) sqrt - 2^2 - 4 (1) (-46) / 2 (1)

    x = 2 (+-) sqrt 4 + 184) / 2

    x = 2 (+-) sqrt 188) / 2

    x = 1 (+-) sqrt 47
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