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12 December, 07:56

1.) What is the vertex of the quadratic function y=x^2-4x-1

2.) What is the solution set for the quadratic function y=x^2-4x-21

3.) What are the solutions to the quadratic equation (x+9) (x-1) = 0

4.) What are the zeros for the quadratic function f (x) = x^2+10+25

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  1. 12 December, 10:11
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    1. Solve by differentiation (Derivative = 0 at the vertex)

    dy/dx = 2x-4

    0=2x-4

    0=2 (x-2)

    x=2

    when x=2 y=-5

    therefore vertex (2,-5)
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