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14 October, 16:18

What minimum radius must a large conducting sphere of an electrostatic generating machine have if it is to be at 20000 V without discharge into the air?

How much charge will it carry?

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  1. 14 October, 17:35
    0
    First of all,

    The electric field at the surface of the sphere is given by

    E = kQ/r²

    The field strength at which breakdown occurs in the air is 3.0 MV/m

    So, E = 3.0 MV/m

    The sphere potential is defined as

    V = kQ/r

    If we divide E/V we get

    E = V/r

    r = V/E = 20000V / 3.10^6 V/m = 6.66 10^-3 m = 6.66 mm

    2. Charge

    V = kQ/r ... >>

    Q = Vr/k = 20000V * (6.66 10^-3 m) / (9.10^9 N m2/C2) = 1.481 10^-8 C
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