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20 July, 00:08

A boulder with a mass of 2,500 kg on a ledge 200 m above the ground falls. Estimate the speed of the boulder just before it hits the ground.

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  1. 20 July, 02:22
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    Using vf^2 = vi^2 + 2gh, theres no initial velocity so this can be rewritten to

    v^2 = 2gh or v = sqrt (2gh)

    v = sqrt (2*200m*9.81m/s^2)

    v = 62.6418 m/s

    v = 62.6 m/s
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